We can state the problem mathematically.
Let G be an undirected graph with set of vertices V and set of edges E.
Let
be a directed graph obtained from G by replacing each edge
with a pair of directed edges e+, e- with opposite orientation.
If e is incident to vertices ve,we then we write
e+=(ve,we) and
e-=(we,ve).
A path
in
is a strand path if p is a
loop (starts and ends at the same vertex) such that
if
(
). In particular, e+e- is a strand path
for each edge
.
The graph G is s-DNA covered if there are s strand paths
in
such that for every edge e of
there is a unique i such that pi passes through e.
Using the construction from the previous section we can easily show that
every graph can be s-DNA covered for some s. In the DNA graph structure
every DNA strand corresponds to a strand path p.
We denote with c(G) the minimum of all s such that G is s-DNA covered.
Problem 1: given a graph G, determine c(G).
Problem 2:
characterize graphs G such that c(G)=1.
We refer to the graph in Fig. 2. Two different
DNA structures of the same graph are presented in Fig. 4
and in
Fig. 8. In the first case, G is 3-DNA covered and in the second
case it is 1-DNA covered. So c(G)=1.
Every vertex in a graph (with degree greater than 2) can be described by 3-junction molecules (by extending the body of the central part of the vertex molecule) [28]. In Fig. 10 two 3-junction molecules presenting one vertex are depicted. The difference between these two molecules is in the connection between the edges (arms) that is established. The molecule (b) is essentially same as the molecule (a). If we twist the sides B and C in (b) so that C comes at the top and B comes on the right, we have the same structure molecule as in (a). [We note that ``twist''is used only intuitively for the purpose of the theoretical argument. Twist might not be a good way to show differences in configuration for DNA [28]. If we set a reference point at A, a half-turn difference in the length of the double helix at side A reverses the positions of B and C in space.]
When the 3-arm branched molecule becomes part of a 3D DNA structure, the three single strands can be part of three, two or one circular single stranded molecule. If they are part of three circular single stranded molecules then, as shown in Fig.11 (i.a), by changing the connection from (a) to (b) in Fig.10, the three circular single stranded DNA molecules become one. After the change in the connection, one circular single stranded DNA molecule either becomes three (as in Fig.11 (i.a)) or remains to be one. (Fig.11 (i.b)). If we have two circular single stranded DNA molecules, by changing in between connections ((a), (b) in Fig.10) the number of strands remains at 2 (Fig.11 (ii)).
We say that a graph is weakly connected if there is an edge e such that if we remove e from G then G becomes disconnected. Using the change of connections within 3-armed branched molecules as shown in Fig.11 we can show the following:
Proposition.
If G is a planar graph that is not weakly connected, then
.
There are examples of planar weakly connected graphs with c(G)>2.
We are not sure whether the above proposition holds for graphs with
arbitrary genus.